Source code for elephant.signal_processing

# -*- coding: utf-8 -*-
'''
Basic processing procedures for analog signals (e.g., performing a z-score of a
signal, or filtering a signal).

:copyright: Copyright 2014-2016 by the Elephant team, see AUTHORS.txt.
:license: Modified BSD, see LICENSE.txt for details.
'''

from __future__ import division, print_function
import numpy as np
import scipy.signal
import quantities as pq
import neo


[docs]def zscore(signal, inplace=True): ''' Apply a z-score operation to one or several AnalogSignal objects. The z-score operation subtracts the mean :math:`\\mu` of the signal, and divides by its standard deviation :math:`\\sigma`: .. math:: Z(x(t))= \\frac{x(t)-\\mu}{\\sigma} If an AnalogSignal containing multiple signals is provided, the z-transform is always calculated for each signal individually. If a list of AnalogSignal objects is supplied, the mean and standard deviation are calculated across all objects of the list. Thus, all list elements are z-transformed by the same values of :math:`\\mu` and :math:`\\sigma`. For AnalogSignals, each signal of the array is treated separately across list elements. Therefore, the number of signals must be identical for each AnalogSignal of the list. Parameters ---------- signal : neo.AnalogSignal or list of neo.AnalogSignal Signals for which to calculate the z-score. inplace : bool If True, the contents of the input signal(s) is replaced by the z-transformed signal. Otherwise, a copy of the original AnalogSignal(s) is returned. Default: True Returns ------- neo.AnalogSignal or list of neo.AnalogSignal The output format matches the input format: for each supplied AnalogSignal object a corresponding object is returned containing the z-transformed signal with the unit dimensionless. Use Case -------- You may supply a list of AnalogSignal objects, where each object in the list contains the data of one trial of the experiment, and each signal of the AnalogSignal corresponds to the recordings from one specific electrode in a particular trial. In this scenario, you will z-transform the signal of each electrode separately, but transform all trials of a given electrode in the same way. Examples -------- >>> a = neo.AnalogSignal( ... np.array([1, 2, 3, 4, 5, 6]).reshape(-1,1)*mV, ... t_start=0*s, sampling_rate=1000*Hz) >>> b = neo.AnalogSignal( ... np.transpose([[1, 2, 3, 4, 5, 6], [11, 12, 13, 14, 15, 16]])*mV, ... t_start=0*s, sampling_rate=1000*Hz) >>> c = neo.AnalogSignal( ... np.transpose([[21, 22, 23, 24, 25, 26], [31, 32, 33, 34, 35, 36]])*mV, ... t_start=0*s, sampling_rate=1000*Hz) >>> print zscore(a) [[-1.46385011] [-0.87831007] [-0.29277002] [ 0.29277002] [ 0.87831007] [ 1.46385011]] dimensionless >>> print zscore(b) [[-1.46385011 -1.46385011] [-0.87831007 -0.87831007] [-0.29277002 -0.29277002] [ 0.29277002 0.29277002] [ 0.87831007 0.87831007] [ 1.46385011 1.46385011]] dimensionless >>> print zscore([b,c]) [<AnalogSignal(array([[-1.11669108, -1.08361877], [-1.0672076 , -1.04878252], [-1.01772411, -1.01394628], [-0.96824063, -0.97911003], [-0.91875714, -0.94427378], [-0.86927366, -0.90943753]]) * dimensionless, [0.0 s, 0.006 s], sampling rate: 1000.0 Hz)>, <AnalogSignal(array([[ 0.78170952, 0.84779261], [ 0.86621866, 0.90728682], [ 0.9507278 , 0.96678104], [ 1.03523694, 1.02627526], [ 1.11974608, 1.08576948], [ 1.20425521, 1.1452637 ]]) * dimensionless, [0.0 s, 0.006 s], sampling rate: 1000.0 Hz)>] ''' # Transform input to a list if type(signal) is not list: signal = [signal] # Calculate mean and standard deviation m = np.mean(np.concatenate(signal), axis=0) s = np.std(np.concatenate(signal), axis=0) if not inplace: # Create new signal instance result = [] for sig in signal: sig_dimless = sig.duplicate_with_new_array( (sig.magnitude - m.magnitude) / s.magnitude) / sig.units result.append(sig_dimless) else: result = [] # Overwrite signal for sig in signal: sig[:] = pq.Quantity( (sig.magnitude - m.magnitude) / s.magnitude, units=sig.units) sig_dimless = sig / sig.units result.append(sig_dimless) # Return single object, or list of objects if len(result) == 1: return result[0] else: return result
[docs]def butter(signal, highpass_freq=None, lowpass_freq=None, order=4, filter_function='filtfilt', fs=1.0, axis=-1): """ Butterworth filtering function for neo.AnalogSignal. Filter type is determined according to how values of `highpass_freq` and `lowpass_freq` are given (see Parameters section for details). Parameters ---------- signal : AnalogSignal or Quantity array or NumPy ndarray Time series data to be filtered. When given as Quantity array or NumPy ndarray, the sampling frequency should be given through the keyword argument `fs`. highpass_freq, lowpass_freq : Quantity or float High-pass and low-pass cut-off frequencies, respectively. When given as float, the given value is taken as frequency in Hz. Filter type is determined depending on values of these arguments: * highpass_freq only (lowpass_freq = None): highpass filter * lowpass_freq only (highpass_freq = None): lowpass filter * highpass_freq < lowpass_freq: bandpass filter * highpass_freq > lowpass_freq: bandstop filter order : int Order of Butterworth filter. Default is 4. filter_function : string Filtering function to be used. Either 'filtfilt' (`scipy.signal.filtfilt()`) or 'lfilter' (`scipy.signal.lfilter()`). In most applications 'filtfilt' should be used, because it doesn't bring about phase shift due to filtering. Default is 'filtfilt'. fs : Quantity or float The sampling frequency of the input time series. When given as float, its value is taken as frequency in Hz. When the input is given as neo AnalogSignal, its attribute is used to specify the sampling frequency and this parameter is ignored. Default is 1.0. axis : int Axis along which filter is applied. Default is -1. Returns ------- filtered_signal : AnalogSignal or Quantity array or NumPy ndarray Filtered input data. The shape and type is identical to those of the input. """ def _design_butterworth_filter(Fs, hpfreq=None, lpfreq=None, order=4): # set parameters for filter design Fn = Fs / 2. # - filter type is determined according to the values of cut-off # frequencies if lpfreq and hpfreq: if hpfreq < lpfreq: Wn = (hpfreq / Fn, lpfreq / Fn) btype = 'bandpass' else: Wn = (lpfreq / Fn, hpfreq / Fn) btype = 'bandstop' elif lpfreq: Wn = lpfreq / Fn btype = 'lowpass' elif hpfreq: Wn = hpfreq / Fn btype = 'highpass' else: raise ValueError( "Either highpass_freq or lowpass_freq must be given" ) # return filter coefficients return scipy.signal.butter(order, Wn, btype=btype) # design filter Fs = signal.sampling_rate.rescale(pq.Hz).magnitude \ if hasattr(signal, 'sampling_rate') else fs Fh = highpass_freq.rescale(pq.Hz).magnitude \ if isinstance(highpass_freq, pq.quantity.Quantity) else highpass_freq Fl = lowpass_freq.rescale(pq.Hz).magnitude \ if isinstance(lowpass_freq, pq.quantity.Quantity) else lowpass_freq b, a = _design_butterworth_filter(Fs, Fh, Fl, order) # When the input is AnalogSignal, the axis for time index (i.e. the # first axis) needs to be rolled to the last data = np.asarray(signal) if isinstance(signal, neo.AnalogSignal): data = np.rollaxis(data, 0, len(data.shape)) # apply filter if filter_function is 'lfilter': filtered_data = scipy.signal.lfilter(b, a, data, axis=axis) elif filter_function is 'filtfilt': filtered_data = scipy.signal.filtfilt(b, a, data, axis=axis) else: raise ValueError( "filter_func must to be either 'filtfilt' or 'lfilter'" ) if isinstance(signal, neo.AnalogSignal): return signal.duplicate_with_new_array(np.rollaxis(filtered_data, -1, 0)) elif isinstance(signal, pq.quantity.Quantity): return filtered_data * signal.units else: return filtered_data
[docs]def hilbert(signal, N='nextpow'): ''' Apply a Hilbert transform to an AnalogSignal object in order to obtain its (complex) analytic signal. The time series of the instantaneous angle and amplitude can be obtained as the angle (np.angle) and absolute value (np.abs) of the complex analytic signal, respectively. By default, the function will zero-pad the signal to a length corresponding to the next higher power of 2. This will provide higher computational efficiency at the expense of memory. In addition, this circumvents a situation where for some specific choices of the length of the input, scipy.signal.hilbert() will not terminate. Parameters ----------- signal : neo.AnalogSignal Signal(s) to transform N : string or int Defines whether the signal is zero-padded. 'none': no padding 'nextpow': zero-pad to the next length that is a power of 2 int: directly specify the length to zero-pad to (indicates the number of Fourier components, see parameter N of scipy.signal.hilbert()). Default: 'nextpow'. Returns ------- neo.AnalogSignal Contains the complex analytic signal(s) corresponding to the input signals. The unit of the analytic signal is dimensionless. Example ------- Create a sine signal at 5 Hz with increasing amplitude and calculate the instantaneous phases >>> t = np.arange(0, 5000) * ms >>> f = 5. * Hz >>> a = neo.AnalogSignal( ... np.array( ... (1 + t.magnitude / t[-1].magnitude) * np.sin( ... 2. * np.pi * f * t.rescale(s))).reshape((-1,1))*mV, ... t_start=0*s, sampling_rate=1000*Hz) >>> analytic_signal = hilbert(a, N='nextpow') >>> angles = np.angle(analytic_signal) >>> amplitudes = np.abs(analytic_signal) >>> print angles [[-1.57079633] [-1.51334228] [-1.46047675] ..., [-1.73112977] [-1.68211683] [-1.62879501]] >>> plt.plot(t,angles) ''' # Length of input signals n_org = signal.shape[0] # Right-pad signal to desired length using the signal itself if type(N) == int: # User defined padding n = N elif N == 'nextpow': # To speed up calculation of the Hilbert transform, make sure we change # the signal to be of a length that is a power of two. Failure to do so # results in computations of certain signal lengths to not finish (or # finish in absurd time). This might be a bug in scipy (0.16), e.g., # the following code will not terminate for this value of k: # # import numpy # import scipy.signal # k=679346 # t = np.arange(0, k) / 1000. # a = (1 + t / t[-1]) * np.sin(2 * np.pi * 5 * t) # analytic_signal = scipy.signal.hilbert(a) # # For this reason, nextpow is the default setting for now. n = 2 ** (int(np.log2(n_org - 1)) + 1) elif N == 'none': # No padding n = n_org else: raise ValueError("'{}' is an unknown N.".format(N)) output = signal.duplicate_with_new_array( scipy.signal.hilbert(signal.magnitude, N=n, axis=0)[:n_org]) return output / output.units